And when I do that, I get a mass of 176.06 grams per mol.

But note, I'm not done there because this is not a mass, this is a molar mass.

It tells me how many grams I have per mol of C6H8O6.

Now, I need to use that along with the mols of sample I

was given in the problem to find the mass of that particular sample.

And so when I look at the numbers about trying to decide where to

start I notice that this number only has one unit associated with it.

And so that's typically where I'm going to start the problem.

So I have 0.650 mols of C6H8O6.

Now I need to use the molar mass in

such a way that the moles will cancel out with one another.

And to do that I'm going to have to have mols on the bottom of this next step,

so I get 176.06 grams per mol of C6H8O6.

Now I see that mols of the vitamin C cancel with mols of vitamin C,

and the units I'm left with are grams of vitamin C.

So now I can simply do the math, and

multiply 0.650 times the 176.06, and

what I end up with is 114 grams of C6H806, and this is reasonable.

I notice that I have a little more than half a mol of my compound, and

what I have is a little more than half the mass of a single mol of the compound.