Like this, we still have our 4 kilo ohm from the top

to the bottom of the circuit and we also have the 6 kilo

ohm From the top to the bottom of the circuit.

So, our RAB remains the same.

On the left hand side of the circuit we have a 4 kilo ohm resistor,

a 6 kilo ohm resistor like this.

So, while we slowly whittling the circuit down to an equivalent resistance.

So again, as we have before, we can see that this series combination

of 2 kilo ohm and 4 kilo ohm will give us an equivalent 6 kilo ohm resistance.

We then can take that equivalent 6 kilo ohm and

we will see it's in parallel with the existing 6 kilo ohm

resistor that's already in the circuit, and so we have a 6 kilo ohm.

And parallel with a six kilo ohm and

that gives us a three kilo ohm equivalent resistance.

And so once again, we're going to redraw the circuit so

we're going to go down here and

redraw it with our two kilo ohm in there, we haven't really modified that yet.

And we have the 4 kilo ohm, we haven't use that,

it combined that into our problem yet.

But we have the rest of the circuit combined and

I guess there's a three kilo ohm on the right-most side of the circuit.

So if we redraw it and we put it in our vise the 2 kilo ohms, 4 kilo ohms,

and 3 kilo ohms for our resistors, and ultimately we want to find RAB.

So, now it's becoming an easier and easier problem to work.

Okay, so in our resistor network,

we also have this 9k resistor at the bottom of the network and

we're going to add that into our network.

On the right most circuit like this and

we're also going to add it to our bottom circuit like this.

So, we have this 9k resistor that needs to be added in to each one of those circuits.

And so if we do that, we can then rewrite our circuit one more time

with the two kilo ohm resistor at the top.

A three kilo ohms resistor at the rightmost side,

combine with a 9k, and we still have the 4k here.

So we have a 2 kilo ohm resistor at the top, 4 kilo ohm top to bottom,

and then a 12 kilo ohm resistor on the right hand side of our circuit.