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In this video, I will sketch for you, a way to do a general analysis of the

two-terminal MOS structure. We will develop equations that will be

valid for any surface condition. Be it accumulation, depletion, or

inversion. Here is the structure we have been

discussing. The general MOS structure with the general

voltage Vgb. The surface potential, between surface and

bulk, is Cs. The oxide potential is Cox.

And at any point y, the potential between that point and the bulk is C of y.

We need to write equations for this structure, that can predict what will

happen. For any value of V-gv, whether it is in

depletion, or in, at flat band, or in inversion or in accumulation.

We have to start like this. And once we have the general expressions

then we will simplify for particular regions, notably the regions of the

inversion that we are mostly interested in.

1:07

So we start with this equation, which that we have already used.

This relates, the, ratio of electron concentration at the point y, to, the

bulk, so n of y to n, n zero. And we have the exponential that we

involves the potential from the point we're interested in to the[INAUDIBLE] of y

divided by the thermal voltage. We already know that there is a

corresponding equation for holes, which is the same form, except it has a minor sign

here. And we also know that the total density at

any point y, in general Can consist of holes and electrons and ionized acceptor

atoms and ionized donor atoms with these sins.

We covered this in our background review. Finally, we have related charge density to

potential by using Poisson's equation, which is shown here.

Second derivative of, the potential with respect to position.

Rho is the total density over here. Epsilon sub s is the permittivity.

Now, if you manipulate these equations, you can derive the following result.

I'm going to bypass a lot of mathematical steps.

If you are interested, you can find them in Appendix C of the book.

So starting from this equations, we get this result.

It looks kind of very long but in fact it is written in a form that is probably

clearer than any form you may have seen in the semiconductor books.

The reason is that if you trace the development of this equation, you can

clearly identify where each term comes from.

This one comes from the hole contribution, if you have any holes in the surface, for

example, in the accumulation. This comes from, ionized acceptor atoms,

and we even allow for the presence of donor atoms, at the same time.

I forgot to say that this is possible in general because sometimes you may have a,

an n-type region, and to convert it into a p-type region You diffuse enough acceptor

atoms, so that the overall population of acceptors is larger than that of donors.

And the difference is the effective acceptor concentration.

So to allow for such a general situation, I have allowed both of our n sub a, and n

sub b. N sub d here.

And finally, this term is due to electrons.

This is the contribution of electrons to the whole chart.

So now we an equation that gives you the total charge Qc per unit area, that's what

the prime sign means here, as a function of the service potential.

This term here sign of Cs is simply one if Cs is positive.

It is, zero if Cs is zero, and it is equal to, minus one, if Cs is negative.

If you work with this equation. And, you make certain assumptions and

substitutions, again I have to skip the steps, but they are in the book.

You find this equation which is closer to the equation you see in semiconductor

device books. So here is a repeat of this equation.

It relates the total charge in the semiconductor to Cs,work Cs is the surface

potential. We also know that the gate charge is the

oxide capacitance times. The oxide potential.

This is the same as what you will have in the linear capacitor.

We also know that the sum of the gate charge, effective interface charge, and

space charge, is zero. Finally we have the, potential balance

equation, which we have shown before, and it is this one.

Now, if you look at this set of equations, what do you see?

You see four equations in foreign nodes. Vgb is applied externally, so this is

supposed to be a known voltage. The only unknowns are 2 charges.

[inaudible] charge, and semi conductor charge.

And two potentials. The ox side potential, and the surface

potential. Now in principle having four equations and

four unknowns you should be able to solve them.

Unfortunately because of this equation, it's not possible to really have explicit

solutions, so you must resort to numerical solutions for this.

Nevertheless, we can do something useful here.

We're going to eliminate some unknowns between these equations and end up with

this equation. What is this equation?

This equation relates the surface potential of Cs, which appears at various

places here To the externally applied voltage.

So in principle now we have finally a result that allows us to calculate the

surface potential as a faction of the externally applied voltage.

If we know the surface potential then we can find the[UNKNOWN] charged and we can

end up with the MS transistor equations. And that is why we are dealing with this.

This is probably the longest equation we'll ever see in this book, and pretty

soon I'm, I'm going to simplify it further.

This quantity here, the square root divided by C ox prime will be called

gamma. This will turn out to be the body effect

coefficient that you may have actually already used in simple models for

[unknown] transistors. We'll come back to that.

7:10

So let's see what these plots look like. This is, what I just mentioned.

The plot of CS versus VGB, and I subtracted, the Flatman voltage here, to

make things cleaner. This is the total semiconductor charge, as

a function of the same quantity, Vgb minus the flat band voltage.

So let's interpret these plots, having in mind this general structure.

So let's start with the charge. It says that if Vgb minus Vfb is negative,

in other words Vgb is less than Vfb, we are in accumulation, and the charge is

positive. It should be because over here we would

get holes in accumulation as we have already discussed.

Then if Vgb starts becoming larger than Vfb, so when this is positive, we have

depletion. The charge becomes negative and increases,

because we are depleting acceptor atoms. And finally, when this is large enough,

you start getting electrons at the surface.

And now the charge becomes significantly more negative because of the presence of

electrons. Let's look at this plot.

When Vgb minus Vfb is negative, we are in accumulation, and the surface potential is

negative, as we have already mentioned. When we are in depletion, the surface

potential is positive, and it depletes the semiconductor.

You have ionized acceptor atoms And as you increase vgb, you deplete more and more.

And the surface potential goes up. And finally, the surface potential

flattens up, out like this. Why does this happen?

It happens because, at such values of vgb, the surface potential is so large over

here. That it's, the surface starts becoming

very attractive for electrons. You may recall that the concentration of

electrons at the surface is exponentially related to the surface potential.

So once that exponential takes off. Then, you can have plenty of extra charges

here without having to increase cs very much.

So as Vgb becomes large the charge, in the semiconductor which will start being

mostly due to electrons can become large without having to increase the surface

potential very much. Now, here this region is called inversion.

We can define it more precisely later on. I would like to mention this preliminary

fact here that the beginning part of the inversion is the weak inversion.

Start again. The beginning of this region is weak

inversion. Then we get into moderate inversion, and

when this flattens out we are in strong inversion.

We will come back and define these things more precisely later on.

Now we can simply these results in particular regions.

10:03

Let's for example assume that we are deep in depletion, where CS is positive, and

deep in depletion means we have a CS larger than several phi t, but not as high

as phi F. So now, certain, terms, become completely

negligible. And we also know the sign over here.

The sign of c s is positive, because we are in, depletion.

Therefore, the function sign[INAUDIBLE] s is equal to plus one.

This term is completely negligible because it is, ex-, an exponential, with a

negative quantity and the, absolute value of the quantity's large.

So this we can neglect. The same thing happens here.

This is an extremely small quantity multiplying this whole thing.

So you can forget about all this. And even phi T can be neglected compared

to Cs so sometimes we like to leave phi-T there but it really does not make much

difference for our purposes so I will. Be neglecting it.

You can do the same with the equation we had for VGB versus CS.

And we get the corresponding equation like this.

So now we have simple results for deep and depletion, let me summarize the results.

This equations after you eliminate these extremely small terms become like this.

This is the charge. And, this is, the gate body voltage.

Notice now we have very simple expressions.

The charge in the semiconductor in depletion, which is due to ionized

acceptor atoms, is proportional to, the square root of the surface potential.

And VGB is related to[INAUDIBLE] in this way.

Remember that in the general equation we had that related VGB to[INAUDIBLE], we

could not solve explicitly for[INAUDIBLE]. But this one of course we can solve

explicitly for[INAUDIBLE], and the result is this.

So this now gives you the surface potential for a given vgb, explicitly.

This expression, which is the surface potential in depletion, will be called csa

and we will have use for it pretty soon. Here is a plot of Cs versus Vgb minus the

flat[UNKNOWN] voltage. As you, we've seen in the previous slide

it flattens out like this in strong inversion.

And Csa is this expression, and it goes like that.

You can see now that in depletion, the two are extremely accurate.