[MUSIC] Now we're going to introduce a mutagen. This mutagen is hydroxylamine. Hydroxylamine, Is a very simple chemical that will react with C residues to make something, and I don't draw you the chemical structure, that is like a C-star or a C-circle or whatever you want to call it. Some people call it u-prime. It's like a U residue. This normally pairs with G. This will pair with A. So this is how it's a mutagen. You make a C into something that will code for an A. This mutagen can be used with viruses with phage in suspension. So you can take a phage, lysate, which has a head, a tail and fibers. And inside the head, you have the DNA. If you treat this with hydroxylamine, and you don't have too much of it, or you don't wait too long, you will, on the average, have maybe one hit per molecule, maybe two hits per molecule somewhere. Most of these hits you will ignore, but if you start with a mutant, you can isolate a revergent and see whether the frequency of reversion is increased. If your mutant is, for instance, CAG, that's your mutant, this can mutate to CAA because you can change the C that is opposite to this G, or to UAG. Now, if you do this with the genesis, the effect will be extremely different, depending on which strand of the DNA is touched. This is a Y tag gene. So on the left you have a piece of DNA that has a G on the top strand, and a C on the bottom strand. This is drawn so that the messenger RNA will have the G. So I will add little arrows to help you. Okay, so you have now two strands of the DNA and the message. You agree that if I by chance hydroxylamine touches this C, and makes a u prime, this u prime will code for A on the message. The bottom strand here is called the sense strand. The top strand is called the antisense strand. Now this is for me, a very confusing way of calling the strands, because it depends on what particular aspect of gene expression you study. If you study transcription this is the sense strand. If you study translation this is the sense strand. So use whatever system you want, but just make sure that everybody agrees on what they use in their own personal system. Brenner, in this paper, uses sense for this message that will be for the strand that will be transcribing to the message. So the message is identical in sequence to the anti-sense. In this case, the C is on the sense strand, which means that as soon as this DNA gets in the cell, the promoter will drive expression of this gene, and will immediately make a mutant RNA. On the right, you have the opposite situation. The C's on the top strand, the anti-sense strand. The G's in the bottom strand. The C's on the message strand. If now in this case, you put the base modification on the top strand, what happens? The top strand is not used for transcription. So the transcript, the messenger RNA will be the same as in the parent. It will be no different. If this is mutant, this is mutant. If this is mutant, this is wanted. That's a big difference between it. So, basically the first thing that Brenner wanted to know was whether amber, nonsense triplet, have a site sensitive to hydroxylamine, i.e a GC. What they did is, they analyzed a series of amber and ochre. You may think that this is overkill. Why do they use so many mutants? It's just to show how general the phenomenon is. And the phenomenon here is to analyze for reversion after DNA replication. So after DNA replication, you don't see an increase in the reversion index of all these mutants except for this mutant, which is not an amber or an ochre. This is a substitution that contains a GC in a mutant there can be reverted by Hydroxylamine. All the other ones can not be reverted by hydroxylamine, which means very simply, the first interpretation would be to say okay, we can not revert by hydroxylamine, so there is no GC in the amber or in the ochre codon. But now, remember the amber is UAG. The ochre is UAA. And you're going to tell me well, the amber has a G so that can't be true. Well, what they say is that the amber and ochre triplets do not contain a GC pair, or if a GC pair is present, that triplet is connected by a GC to AT transition to another nonsense triplet, which is exactly what it is. A GC to AT transition connects the amber to the ochre. Surely it could be another nonsense codon, it doesn't have to be the ochre. But very quickly after that, they discovered that you can convert an ochre into an amber. So again, I write to you what the ochre is, and what the amber is. Amber is UAG. Ochre is UAA. Now, what are the property of an amber, an ochre, and a wild type phage on different strains? If you take a strain that is su0, this will not grow, this will not grow, and this will grow, because they're mutants. If the strain has a su amber, the amber will grow, the ochre will not grow, and the white tab will grow. And if you take now on an su ochre strain, it suppresses both the amber and the ochre. So you can keep an r2 ochre on a su ochre, because it grows. That's the only strain in which it would grow, and of course b. Now, if you take this mutant, this ochre, and you mutagenize it with a mutagen that induces transitions, GC to AT transition, you can get revertance that are Y type, and you can get revertants that are amber. How? What happens when you subject an ochre, all of these are ochres, to a mineral purine as a mutagen? So UAA can becom,e by mutagenesis, CAA. It can become UGA, and it can become UAA. So those are the three transitions that are possible. UAG sorry. Good, okay those are the three transitions that are possible. The three triplets, each triplet that can only go, can only undergo one transition. Okay so this is an amino acid, this is a stop which I didn't know at the time, and this is also a stop. So they take all these ochres, and they look at this continuous reversion, they all revert, which is expected. They don't characterize their revertance. They treated with amino purine, and then they have a lot more revertants. Some of these revertants are y-type. And some of these revertants are amber, which means that in this set of three possible transition, you must have at least one wild-type and one amber. That's what it means. And the amber and the ochre are related by two common bases, UAUA, and one different base, G or A. That's the result of this. Now of course, the numbers themselves may be interesting if you're interested in the landscape of mutagenesis. Because some sides are much more easily mutagenized than others. But this is not what they're interested in. They're interested in the codons. So for them 50 amber, or 2,100 amber is the same. The fact is that there are many more amber induced by germinopuree than the non-induced continual set. That's the point. Now if there is a single transition between the amber and the ochre, they can of course test whether this transition is induced by hydroxylamine or not. Because that would give the direction. Since it is not induced by hydroxylamine, the ocher must have the AT base pair, and the amber must have the GC base pair. And the two other bases should be the same for the amber and the ocher, which is exactly what you have here.