Explore
For Enterprise
Join for Free
Log In

Browse
Search
For Enterprise
Log In
Join for Free

Principal Axes and Principal Moments of Inertia

Loading...

Robotics: Aerial Robotics

University of Pennsylvania

4.5 (2,101 ratings) | 82K Students Enrolled

Course 1 of 6 in the Robotics Specialization

How can we create agile micro aerial vehicles that are able to operate autonomously in cluttered indoor and outdoor environments? You will gain an introduction to the mechanics of flight and the design of quadrotor flying robots and will be able to develop dynamic models, derive controllers, and synthesize planners for operating in three dimensional environments. You will be exposed to the challenges of using noisy sensors for localization and maneuvering in complex, three-dimensional environments. Finally, you will gain insights through seeing real world examples of the possible applications and challenges for the rapidly-growing drone industry. Mathematical prerequisites: Students taking this course are expected to have some familiarity with linear algebra, single variable calculus, and differential equations. Programming prerequisites: Some experience programming with MATLAB or Octave is recommended (we will use MATLAB in this course.) MATLAB will require the use of a 64-bit computer.

Skills You'll Learn

Motion Planning, Robotics, Quadcoper, Matlab

Reviews

4.5 (2,101 ratings)

5 stars
1,436 ratings
4 stars
487 ratings
3 stars
97 ratings
2 stars
42 ratings
1 star
39 ratings

CG

Feb 12, 2016

Well balanced mix of theory and practical applicability. Explanation of the material is also very good.\n\nThe assignments are nicely built on the taught material to stimulate understanding.

UM

Apr 08, 2019

The course is very good and is designed such that even beginners can get a good grasp on the content that is made available. The discussion forums are great and help in making life easier.

From the lesson

Geometry and Mechanics

Welcome to Week 2 of the Robotics: Aerial Robotics course! We hope you are having a good time and learning a lot already! In this week, we will first focus on the kinematics of quadrotors. Then, you will learn how to derive the dynamic equations of motion for quadrotors. To build a better understanding on these notions, some essential mathematical tools are discussed in supplementary material lectures. In this week, you will also complete your first programming assignment on 1-D quadrotor control. If you have not done so already, please download, install, and learn about Matlab before starting the assignment.

Formulation3:18

Newton-Euler Equations6:05

Principal Axes and Principal Moments of Inertia6:03

Quadrotor Equations of Motion5:13

Supplementary Material: State-Space Form4:32

Supplementary Material: Getting Started With the First Programming Assignment3:22

Taught By

Vijay Kumar
Nemirovsky Family Dean of Penn Engineering and Professor of Mechanical Engineering and Applied Mechanics

Transcript

Before we can write down the rotational equations of motion we have to define principle axes and moments of inertia. A principal axis of inertia is defined obviously by a direction. Let's say u is that direction while u is a unit vector along a principal axis, if I times u is parallel to u. There's a theorem that says that you can always find three such independent principle axes. In other words there are three independent axes such that I times the unit vector along that axis will give you a vector that's parallel to that axis. The moment of inertia is essentially the scaling term. So if I take I times u and it defers from U by a scale of factor, that scale of factor is the moment of inertia. These moments of inertia are called principal moments of inertia. Here's a simple example that illustrates what the moments of inertia tell you. So in this cartoon, you have a rigid frame, A you have a parallel plate that's spinning about a vertical axis, but there are two different configurations. On the right side, the axis is perpendicular to the plate. In fact this configuration is symmetric. On the left side, the configuration is symmetric, but the axis is not perpendicular to the plate. On the right side, if you compute the angular momentum. You'll find that the angular momentum vector and the angular velocity vector are parallel. On the left side, they are not. And this is because the axis of rotation does not coincide with any of the principal axes. Now we're ready to deal with Euler's Equations which will tell us the rotational equations of motion. Again it comes down to this basic observation. The rate of change of angular momentum is equal to the net moment applied to the rigid body. We take C, the center of mass as the origin for all our calculations. In this picture, B1, B2 and B3 are a set of body fixed unit vectors that define a body fixed frame. We'll now insist that these vectors point along principal axes and we'll write our angular velocity as linear combinations of b1, b2, and b3, and the components are omega 1, omega 2, and omega 3. Once again remember, the two key aspects to what we are doing, one is that we're taking c, the center of mass of the origin. Second we're insisting that the body fixed frame in which we'll do our calculations will be along the three principal axes. If you take the basic equation on the top right, you can write the left hand side by breaking it up into two terms. The first term involves the derivative in a body fixed frame. The second term and while it's a correction factor, that correction factor's a vector that takes into account the fact that the differentiation is done in the body fixed frame. This correction factor is simply the angular velocity of the moving body fixed frame crossed with the angular momentum. So this correction factor as I paraphrased it, is actually a well-known fact in mechanics. Anytime you differentiate a vector in a moving frame, it's derivative is different from the derivative in a fixed frame. The difference is obtained by simply factoring in the cross product of the angular velocity with that vector. But first term on the left hand side can be written in terms of inertia matrix times the angular velocity vector. Because we have chosen principle axes, it turns out that the off diagonal elements in the inertia tensor are zero. So therefore the first term which involves I times omega, the inertia tensor times the angular velocity vector consists of three terms. The diagonal terms I11, I22, I33, which multiply with omega1, omega2, and omega3, yield three terms that you see on the right hand side. The second term on the left hand side of the equation immediately above that which is omega cross H can be written again in component form. And that gives you the matrix equation that you see on top. These are Euler's Equations of Motion. You can see they're quite compact. The first term Is essentially the derivative of the angular momentum in a body fixed frame. The second term is the correction. The third term, the term on the right hand side, is the net moment. In what follows we will use p,q and r to denote the components of the angular velocity vector along b1, b2, and b3.

Explore our Catalog

Join for free and get personalized recommendations, updates and offers.

Coursera provides universal access to the world’s best education, partnering with top universities and organizations to offer courses online.

© 2019 Coursera Inc. All rights reserved.

Get it on Google Play

Coursera
About
Leadership
Careers
Catalog
Certificates
MasterTrack™ Certificates
Degrees
For Enterprise
For Government
For Campus

Community
Learners
Partners
Developers
Beta Testers
Translators

Connect
Blog
Facebook
LinkedIn
Twitter
Instagram
YouTube
Tech Blog

More
Terms
Privacy
Help
Accessibility
Press
Contact
Directory
Affiliates