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`0``4``8``0,8`

Answer :

`D`Solution :

Given equation is `2x^(2)-kx+k=0` <br> On comparing with `ax^(2)+bx+c=0` we get <br> `a=2,b=-k` and `c=k` <br> For equal roots, the discriminant must be zero.<br> i.e., `D=b^(2)-4ac=0` <br> `= (-k)^(2)-4(2)k=0` <br> `implies k^(2)-8k=0` <br> `implies k(k-8)=0` <br> `:. k=0,8` <br> Hence the required values of `k` are 0 and 8.Transcript

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00:00 - 00:59 | hi students are question is values of K for which the quadratic equation 2 x square minus kx + K is equal to zero has equal roots is firstly the standard form of quadratic equation is X square + bx + c is equal to zero right and the given equation is the given equation is 2 x square minus kx + K is equal to zero write from this on comparing we can say that a is equal to to write b is equal to minus K and C is equal to right now from the question it is given that the equation has equal roots for equal roots does a discriminant should be equal to zero and the formula for calculating the discriminant of the root is b square - 4ac right so we can say that the question is b square - 4ac should be equal to zero right now on comparing be the value of beavers |

01:00 - 01:59 | - 2 - K square - 4 into a to C S K is equal to zero light minus A square is K square - 22 and 24 is 88 K is equal to 0 9 we can take ke common rights to this is equal to K - 8 is equal to zero right so from the from this we can say that K is equal to zero or right kg equal to zero okey - 8 is equal to zero write K is equal to zero ke - 8 is equal to zero the from here ke is equal to 8 to 1 value of k 0 and 1 value of case itself from the options we can say that the correct option for the given equation is option De |

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