Well, we've now discussed the Lennard-Jones inter-molecular potential,
and hopefully you enjoyed the demonstration of the liquefaction of
oxygen from the air. It is inter-molecular interactions that
permit you to liquefy a gas, because the molecules just stick together.
And we got to see some of the more spectacular properties of liquid oxygen.
Today I'd like to spend some time focused on other inter molecular potentials.
Besides Deleanar Jones, because they can provide us with some information that can
be interesting as well. And let me remind you that the virtue of
having the intermolecular potentials potential function.
Is that we have a relationship between the potential.
Written on this slide in terms of u, u is a potential that depends on a in, inter
particle separation r and the second virial coefficient, in this case B2vt.
And so by plugging in a given potential u into that integral expression, we can in
fact compute by solution of the integral B2v, and understand how a real gas will
behave. So, I'd like to pause for a moment before
looking at some different potentials by actually discussing the physics behind
the various pieces of the Leonard Jones potential.
And in particular I'd like to look at the attractive term.
Which has r to the minus 6 dependents. And if we ask what, what sort of physical
interactions do in fact diminish as r to the minus 6 as things grow further apart.
The first is dipole-dipole interactions. So, if our molecule has a permanent
dipole moment, then there are two extreme possibilities for alignment.
One is that the two dipoles are opposed to one another.
So dipole here represented by a negative charge and a positive charge.
And since like charges repel, this would be a bad arrangement of these dipoles.
On the other hand, they can also be head to tail, that is the maximally attractive
arrangement of two dipoles. And, it turns out that the dipole-dipole
interactions between molecules are really quite small compared to thermal energy
for typical molecules and typical temperatures we'd work with And so, the
two dipoles are in fact tumbling with thermal energy, and, as a result we have
to average over the many different accessible orientations.
When one does that averaging, one discovers that the potential of
interaction is given here, it depends on the square of the two individual dipole
moments. Here's where you see temperature playing
a role, because it is causing these dipoles to tumble.
And then here's the r to the minus 6 dependence, and this is the permittivity
of free space. Another r to the 6 interaction is a
dipole-induced dipole interaction. So when a molecule with a permanent
electrical moment, like this one with a dipole is brought up to a molecule that
does not have a permanent moment, maybe it's an atom.
It will polarize the electron cloud of that atom and introduce an induced
dipole. And so, to emphasize that it's induction
I've put these little delta symbols here. It's sort of a small increase in positive
charge, to be near the region of negative charge in the permanent dipole.
And when one works through the electro-statics in that one find that if
you have two systems each of which, each of which does have a permanent dipole but
the drawing here only one of them does. But if they do, this is the most general
formula. Each permanent dipole can induce some
additional dipole in the other. And the net interaction then goes as,
square of the individual dipole moments times the polarizability, that's what
alpha is. So it's the ability to be polarized.
it, that's what it's a measure of. Then again permittivity of free space.
And an r to the minus 6 dependence. And then finally, a very important
interaction that a physical chemist would call dispersion.
And that is induced dipole-induced dipole interactions.
So when two particles with no permanent electrical moments are brought together,
particles with electron clouds, then because those clouds of electrons can
move in a correlated fashion, they will instantaneously arrange themselves to
have a favorable induced dipole, induced dipole interaction.
That's an electron correlation phenomenon.
And again, the equation has an r to the minus 6 dependence.
It involves the ionization potentials of the two particles.
There are polarize abilities and again the permittivity of free space.
So, it turns out that although all of these different kinds of interactions
show r to the minus 6 behavior, really the dispersion interactions dominate.
They form up the largest percentage of the total interaction energy between two
molecules. Dispersion are important, let's take one
more moment to take a look at it. It was first
Given this relatively simple formula and described by Fritz London.
It's a purely quantum mechanical effect. It has no classical analog.
So, it happens because of the correlated motions of electrons in quantum
particles. If you just bring two uncharged classical
species together in physics, they have no electrical interaction, they have no
electrical moments. Nothing.
But when the electrons are in motion about a nucleus, you can induce these
moments. And as I mentioned on the on the last
slide, these i terms appearing in the numerator are ionization energies, and
they could be given in joules, for instance.
Polarizability, which is the, the propensity to allow and induce dipole to
be induced in your electron cloud about a nucleus, that is given in units of
coulometer squared per volt. So, a voltage would be for instance,
field that could induce a dipole. And here's the permittivity of the vacuum
or free space. And I'll just mention again, dispersion
usually the dominant contribution to the r to the minus 6 attractive interaction
that appears as the second term in the Leonard-Jones potential.
Well, let's think about somewhat simpler potentials with the motivation being that
when we plugged the Lennard-Jones potential into the relevant integral in
order to solve for the second virial coefficient we ended up with an integral
that was impossible to solve analytically.
But maybe we can gain a little bit of intuitive insight by using somewhat
simpler forms for the potential where we really can solve that integral.
And so two potentials I want to look at, briefly.
One is the hard-sphere potential, or the billiard-ball potential, you might call
it. So in the hard-sphere potential, for a
separation r greater than sigma, and sigma can be thought of as the diameter
of a sphere, beyond that. Values sigma.
There is no interaction, it's zero. So two things approach one another.
They don't feel each other at all. And then at r equal to sigma, and for all
values below it, the potential becomes infinite.
That is if you, if you think of sigma as being the diameter.
Then if I have two particles. Think of billiard balls that have a
diameter of sigma. I will be able to bring them together
until their two centers are separated by sigma, and at that point, since their
radius is half of sigma, add together two halves of sigma, you'll get a sigma.
At that point, they kiss. And they're billiard balls, they're very
hard, they don't like each other. So, they cannot go any further towards
one another, in a real system, and then they bounce off one another.
But in any case, the potential becomes infinite.
So no interaction, no interaction, no interaction, full stop, infinite
potential. So that's a very easy one to write down.
an alternative is to still have the square wall here, the repulsive wall at
sigma. So still hard-sphere contact.
But, over some interval, as the one sphere departs from the other, there will
be an attractive interaction. And it's a constant, so it's called a
square-well potential, because there is a well below zero in the potential, but it
has a, a flat bottom. And it goes for a certain distance, and
then it ends. And so if we describe that
mathematically, we'd say for r less than sigma, infinite potential between sigma,
and let's use some multiple of sigma. So lambda's just a parameter.
How far out do you feel the attraction? It is minus epsilon.
So minus, meaning it's attractive. An then beyond that multiple of sigma,
it's zero again. So let's see how those potentials behave
when we plug them into the the integral expression for the second virial
coefficient. And let's start with the hard sphere
model. So that has the simplest mathematical
formula. And let's pause for a moment to think,
when might this be a good potential? To describe the interaction between gas
molecules. And so, you would expect it to perhaps be
relatively good at very high temperatures.
At very high temperatures, the molecules are moving with a lot of speed, and so
they don't necessarily need to feel an attraction to be drawn close to another
molecule. Instead, they just keep going till they
slam into one, and then the bounce off one another.
And they behave kind of like billiard balls, if billiard balls were moving with
a lot of kinetic energy. So if the temperature is very high
relative to, epsilon over kb. So that's a, a measure of temperature.
An attractive force divided by Boltzmann's constant.
Then we can pretty much ignore the attractive force.
And only worry about the repulsive part. So if I now take the expression for the
second virial coefficient, and I simply plug in for u here, these values, I see
that really I need to do two integrals. I need to do one integral from 0 to
sigma. And I'll plug in the potential, and it is
infinite, so I get e to the minus infinity.
So that's just 0. And then here's minus one, so I keep
minus 1 r to the 2nd dr and then a second term will go from sigma to infinity.
So, I take e to the minus u but u is now equal to 0 and so e to the 0 is 1 minus
1. This entire integral drops out because I
am just integrating over 0. So, all I am left with is the integral
from 0 to sigma of r squared dr. And of course that is r cubed over 3.
And we evaluate that at it's limits and you end up after multiplying by the
constants as 2 pi, sigma cubed, Avogadro's number divided by 3.
And if you work that out, that's, that's 4 times the volume of Avogadro's number
of spheres, having a diameter of sigma. And so that's kind of a measure of
occluded volume, can be thought of. And that is, what we expect the second
virial coefficient to be a positive number, at high temperature.
Because you can't access the whole volume in an ideal gas good because there is a
finite size to the actual gas molecules. Notice that it's independent of
temperature. Alright, so even though we have here that
B2v is a function of temperature, this says it's just a constant, but if you
remember your your plot of the second virial coefficient as a function of
temperature. You'll recall that it goes up from low
temperature, goes through the boil temperature, and then flattens out at
very high temperatures and it is effectively constant.
So, this is a, a good approximation for that at very high temperature.